if a1,⋯,as are not all of the same sign, then the above equation has solutions in primes 462" title="Click to view the MathML source">pj satisfying pj≪|n|1/k+A3⋅2k−1+ϵ,
if a1,⋯,as are all positive, then the above equation is solvable in prime 462" title="Click to view the MathML source">pj whenever 46b57e650f6cde4a6fa" title="Click to view the MathML source">n≫A3k⋅2k−1+1+ϵ.
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