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A q-enumeration of lozenge tilings of a hexagon with three dents
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文摘
MacMahon's classical theorem on boxed plane partitions states that the generating function of the plane partitions fitting in an a×b×c box is equal to
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where Hq(n):=[0]q!⋅[1]q!…[n−1]q! and View the MathML source. By viewing a boxed plane partition as a lozenge tiling of a semi-regular hexagon, MacMahon's theorem yields a natural q-enumeration of lozenge tilings of the hexagon. However, such q-enumerations do not appear often in the domain of enumeration of lozenge tilings. In this paper, we consider a new q-enumeration of lozenge tilings of a hexagon with three bowtie-shaped regions removed from three non-consecutive sides.

The unweighted version of the result generalizes a problem posed by James Propp on enumeration of lozenge tilings of a hexagon of side-lengths 2n  , e24e41ee03bc80f7bf53ba74222971c7" title="Click to view the MathML source">2n+3, 2n  , e24e41ee03bc80f7bf53ba74222971c7" title="Click to view the MathML source">2n+3, 2n  , e24e41ee03bc80f7bf53ba74222971c7" title="Click to view the MathML source">2n+3 (in cyclic order) with the central unit triangles on the (2n+3)-sides removed. Moreover, our result also implies a q-enumeration of boxed plane partitions with certain constraints.

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