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Synthesis of a Heterometallic Trinuclear Cluster of Ruthenium and Platinum with a Linear Alignment
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A heterobimetallic trinuclear complex of Ru and Pt in a linear alignment, {Cp*Ru(H)2}2(Pt)(μ-PtBu2)2(μ-H)2 (2; Cp* = η5-C5Me5), was synthesized via P–C bond scission upon the photolysis of Cp*Ru(μ-H)4RuCp* (1) in the presence of Pt(PtBu3)2. Complex 2 was alternatively synthesized by the reaction of 1 with Pt(PtBu2H)3, together with the formation of a triangular Ru2Pt complex, (Cp*Ru)2{Pt(PtBu2H)}(μ-PtBu2)(μ-H)3(H)2 (4). X-ray diffraction experiments showed that the structure of 2 could be regarded as a dimer of [Cp*RuH3(PtBu2)] fragments linked by a Pt2+ ion. In contrast to the relevant monometallic trihydrido complex of ruthenium, Cp*RuH3(PtR3), terminal hydrides of 2 were readily substituted by CO and ethylene, leading to the formation of {Cp*Ru(L)}2(Pt)(μ-PtBu2)2(μ-H)2 (5; L = CO, 6; L = C2H4). Such high reactivity could be attributed to the facile formation of a coordinatively unsaturated intermediate owing to stabilization by bulky μ-PtBu2 moieties as well as electronic influence of the central Pt atom. In fact, terminal hydrides of 2 were readily removed upon evacuation, leading to the formation of tetra- and dihydrido complexes (Cp*Ru){Cp*Ru(H)2}Pt(μ-PtBu2)2(μ-H)2 (3) and (Cp*Ru)2Pt(μ-PtBu2)2(μ-H)2 (8), consecutively. Upon hydrogenation, 3 and 8 were smoothly transformed into 2. In contrast with the reactions of 2 with 2e donors, substitution at the Pt atom occurred in reactions with Ph2SiH2 and Et2SiH2, resulting in μ-silylene and μ-silyl complexes {Cp*Ru(H)}{Cp*Ru(PtBu2H)}Pt(μ-PtBu2)(μ-SiPh2)(μ-H)2 (9) and {Cp*Ru(H)2}{Cp*Ru(PtBu2H)}Pt(μ-PtBu2)(μ-η2-SiEt2)(μ-H)2 (10), respectively. In these reactions, the μ-phosphido ligand bridging the Ru and Pt atoms was transformed into a terminal phosphine ligand at the peripheral Ru atom, alongside the formation of μ-silylene and μ-silyl ligands via reductive P–H bond formation.

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